Jekyll and Hyde
6th January 2011, 02:29 PM
So, I got a 10" Vertex rotary table for Christmas, and one of the things I want to do is make dividing plates for it. Yes, I could have bought them, but where would be the fun in that! However, I'm running into a problem which is confusing the hell out of me, and also makes me think that I may have accidentally made a good choice here.
The problem is as follows: While the Vertex manual (https://www.machineryhouse.com.au/images/categories/38121.pdf) shows that for the tables of 8" and above, there are two dividing plates, one with 18 sets of holes and one with 16 sets of holes, every photo I find of the two plates for these tables only have 9 and 8 sets of holes. I've counted a couple of sets on the lower number plate, and worked out that these plates only have every second set of holes on them. The end result being that certain numbers can't be divided with the available plates, like for example 25 (the 30 hole set has been skipped).
As far as I can see, the 6" plates suffer a similar problem, although they have the 'complete' sets of holes on the available plates, the table that tells you which plate and hole set to use for given number of divisions is simply blank for certain divisions - for example, 28 divisions, 51 through 53 divisions, and getting worse as it gets higher.
It seems to me, that if I'm going to make my own dividing plates anyway, I may as well make 4 plates up, and not skip any of the required hole sets at all? Thoughts, corrections? Have I just confused myself or missed something really simple, or is that really how it is?
*EDIT* come to think of it, I could probably make the two plates same as you would buy, and get away with only making one more to cover the 'indivisible' numbers..... Have to sit down and work out how many there are of those....
The problem is as follows: While the Vertex manual (https://www.machineryhouse.com.au/images/categories/38121.pdf) shows that for the tables of 8" and above, there are two dividing plates, one with 18 sets of holes and one with 16 sets of holes, every photo I find of the two plates for these tables only have 9 and 8 sets of holes. I've counted a couple of sets on the lower number plate, and worked out that these plates only have every second set of holes on them. The end result being that certain numbers can't be divided with the available plates, like for example 25 (the 30 hole set has been skipped).
As far as I can see, the 6" plates suffer a similar problem, although they have the 'complete' sets of holes on the available plates, the table that tells you which plate and hole set to use for given number of divisions is simply blank for certain divisions - for example, 28 divisions, 51 through 53 divisions, and getting worse as it gets higher.
It seems to me, that if I'm going to make my own dividing plates anyway, I may as well make 4 plates up, and not skip any of the required hole sets at all? Thoughts, corrections? Have I just confused myself or missed something really simple, or is that really how it is?
*EDIT* come to think of it, I could probably make the two plates same as you would buy, and get away with only making one more to cover the 'indivisible' numbers..... Have to sit down and work out how many there are of those....