Thanks Thanks:  0
Likes Likes:  0
Needs Pictures Needs Pictures:  0
Picture(s) thanks Picture(s) thanks:  0
Page 2 of 3 FirstFirst 123 LastLast
Results 16 to 30 of 35
  1. #16
    Join Date
    May 2005
    Location
    Eden Hills, South Australia
    Age
    63
    Posts
    3,458

    Default

    Quote Originally Posted by Rocker View Post
    ...There still remains, though, the question of the size of the apical angle of the inclined face of the pyramid.
    The angle, v, at the apex of the inclined triangle is (using the notation in the paper), v = 180 - 2u, where u is given by equation (5): u = arccos(d/(2L)). Alternatively, a direct construction yields v = 2 arcsin(d/(2L)). For the example given at the end of the paper, d = 62 mm, h = 20 mm, L = 83.4 mm, both of these expressions give v = 43.6 degrees.

    Update: The case when the pyramid has N sides (rather than the N = 8 case treated in the paper), can be solved using the relation d = 2r sin(180°/N), instead of equation (4) in the paper. From this you can calculate the angle u, and everything else remains unchanged.
    Last edited by zenwood; 31st October 2006 at 12:34 PM. Reason: Generalised to an arbitrary number of sides
    Those are my principles, and if you don't like them . . . well, I have others.

  2. # ADS
    Google Adsense Advertisement
    Join Date
    Always
    Location
    Advertising world
    Age
    2010
    Posts
    Many





     
  3. #17
    Join Date
    Jun 1999
    Location
    Westleigh, Sydney
    Age
    77
    Posts
    9,550

    Default

    Quote Originally Posted by Rocker View Post
    Echidna,

    Actually cutting the triangles safely probably requires a dedicated wide-kerfed crosscut sled, with some auxiliary wedges to give the required apical angle of the triangles.

    Rocker
    To cut the triangles for my polyhedron boxes, I have dedicated X-cut sleds with fences at the correct angles. To put the bevels on the triangles, I make up jigs to hold the triangles, tilt the TS blade to the correct angle and cut. The order in which you cut the sides is important, to avoid splintering away one apex.
    Visit my website
    Website
    Facebook

  4. #18
    Join Date
    Sep 2003
    Location
    Elimbah, QLD
    Posts
    3,336

    Default

    Zenwood,

    I am in envious awe of your mastery of trigonometry Thanks.

    Rocker

  5. #19
    Join Date
    May 2005
    Location
    Eden Hills, South Australia
    Age
    63
    Posts
    3,458

    Default

    It's a pleasure, Rocker. Keen to see what the lid of your box ends up looking like.

    BTW: if you want to find r for a particular value of d, you can invert that last formula:

    r = d / (2 sin (180°/N)).


    I am in envious awe of those old coopers who could put the right bevels on barrel staves using nothing but a plane, a good eye, and trial-and-error.
    Those are my principles, and if you don't like them . . . well, I have others.

  6. #20
    Join Date
    Sep 2003
    Location
    Elimbah, QLD
    Posts
    3,336

    Default

    Zenwood,

    I am not sure that I want to risk ignominious failure by completing a lid for my prototype. The sides are not really high enough to make a worthwhile box by slicing off a section from the top of the sides. Boxes are not really my thing; I prefer furniture, where the occasional minor error is not too noticeable. A box maker must produce perfection, which is not my way I was more interested in making the jig, to show what was possible. I leave it to others with more artistry to make a good box with it.

    Rocker

  7. #21
    Join Date
    Jul 2006
    Location
    Canberra
    Age
    54
    Posts
    914

    Default

    Zen old mate you lost me at u = arcoss(????) What the hell are you trying to do..... Give me a blinkin' head ache.

    Seriously you have done well but I reckon you have a background in rocket science or tertiary level mathematics. Dude I am sorry but that would go in the maybe one day when hell freezes over basket!!!!


    Well done

    Pete
    If you are never in over your head how do you know how tall you are?

  8. #22
    Join Date
    May 2005
    Location
    Eden Hills, South Australia
    Age
    63
    Posts
    3,458

    Default

    Nothing complicated about the arccos, Doughboy: just about every calculator has that button. If I get the inclination, I may implement a spreadsheet to do it automatically.
    Those are my principles, and if you don't like them . . . well, I have others.

  9. #23
    Join Date
    Sep 2006
    Location
    Berowra Heights
    Age
    58
    Posts
    39

    Default

    The arccos is also called the inverse cosine.

    If you don't have a calculator, but are using Windows and the standard calculator, then in scientific mode, you tick the inverse box before clicking the cos button.

    Or you can wait for zenwood to produce a spreadsheet (if you have excel). He will presumably do all the fiddling to turn the numbers from radians (used by default by excel) to degrees, which we understand and shows on our protractors.

  10. #24
    Join Date
    May 2005
    Location
    Eden Hills, South Australia
    Age
    63
    Posts
    3,458

    Default

    Hmmm...cute: the windows calculator is the only one I've seen that has a checkbox for the 'inv' function: why not make it behave like a real calculator and have a button (or shift key) that does this? Also why label the scientific functions in hard to read purple text? Why not relabel the keys to 'arccos' or cos-1 etc. when the 'inv' function is called? Why such a basic range of mathematical functions (no fractions, no combinations or permutations), and why doesn't the inverse factorial work, and why not label the pi button with the greek symbol...?

    Sorry: just another microsoft moment... Not sure I can face Excel today. What to give it a go Trifid?
    Those are my principles, and if you don't like them . . . well, I have others.

  11. #25
    Join Date
    Sep 2006
    Location
    Berowra Heights
    Age
    58
    Posts
    39

    Default Excel spreadsheet

    Well, that certainly sounded like a challenge. Having nothing better to do than work I've given it a go and my effort is attached.

    Attachment 33654

    My maths isn't at Zenwood's level - I've really just followed his workings. I also used his symbols (except that I had to change r to b, because Excel wouldn't let me use r).

    Also, if you only skimmed Zenwood's workings, you might have thought that the mitre at the base of the inclined triangle is e + 90°. That is actually the angle at the corner of the mitred side. I've added a new calculation for the mitre at the base of the triangle (t). Zenwood might want to check my calculation for this.

    Oh and Rocker, an idea. If your sides are actually 62mm, then I recommend an apex height of 13.87. that will make your mitres as close as damn it to 86° (sides) and 100.5° (base), which is nice easy numbers to find on your protractor.

  12. #26
    Join Date
    Feb 2005
    Location
    East Bentleigh, Melbourne, Vic
    Age
    68
    Posts
    4,494

    Default

    Quote Originally Posted by Trifid View Post
    Well, that certainly sounded like a challenge. Having nothing better to do than work I've given it a go and my effort is attached.

    Attachment 33654

    .
    Trifid,

    You're a scholar and a gentleman! Thanks for posting that; saved to my collection of reference do-dads. Working such matters out myself makes what few lumps of grey matter that I may have left ache (and that generally means taking some medicinal Red, which completely buggers the calculation :eek: )

  13. #27
    Join Date
    May 2005
    Location
    Eden Hills, South Australia
    Age
    63
    Posts
    3,458

    Default Calculating mitre angles for regular multi-sided pyramids

    The document has been updated to include the general case of an N-sided pyramid, and also includes the bottom mitre angle, as suggested by Trifid.

    Trifid: Excellent job on that spreadsheet. I wasn't sure exactly what you meant by the base mitre angle, so I calculated one according the the updated document. One slight glitch: I get a different value to yours for the example: 95.7º, compared to your 104.96º; so I'm not sure if we mean the same thing, or whether one of us has made a mistake. I checked my result using the measurement function within Sketchup and it came out pretty close.

    Another thorn is that the document is now over the 100kB limit on this forum, so I've uploaded it to

    http://www.wikiupload.com/download_page.php?id=27126

    Navigate to this URL, then click on the "Download File" button, enter the hard-to-read code letters, then click 'get'.

    Here's another challenge: what are the pyramid dimensions that yield integer values for the mitre angles?
    Those are my principles, and if you don't like them . . . well, I have others.

  14. #28
    Join Date
    Sep 2006
    Location
    Berowra Heights
    Age
    58
    Posts
    39

    Default

    Zenwood,

    Where does it "get" it to? When I click get my screen just blinks and returns to the wiki-upload screen.

    The base mitre that I was referring to is the one marked on your diagram in post #9 - my calculation is spot on on the number you showed there, which is why I believed it was right.

  15. #29
    Join Date
    May 2005
    Location
    Eden Hills, South Australia
    Age
    63
    Posts
    3,458

    Default

    'Get' on the wikiupload page initiates a download of the pdf file, which should be rendered in your browser after a few seconds of download time (it's a 144 kB file, and I'm using Firefox 2.0). From there, you should be able to do a 'save' to your local machine. 'course, you'll need a pdf plug-in.

    I realised what base angle you meant as soon as I'd posted my message. We're both right, we just meant different things.

    I'll update the document, and repost it with all three mitre angles. But it may take a couple of days.
    Those are my principles, and if you don't like them . . . well, I have others.

  16. #30
    Join Date
    Oct 2006
    Location
    Seattle, Washington, USA
    Posts
    166

    Default

    Quote Originally Posted by Rocker View Post
    Zenwood,

    I am not sure that I want to risk ignominious failure by completing a lid for my prototype. The sides are not really high enough to make a worthwhile box by slicing off a section from the top of the sides. Boxes are not really my thing; I prefer furniture, where the occasional minor error is not too noticeable. A box maker must produce perfection, which is not my way I was more interested in making the jig, to show what was possible. I leave it to others with more artistry to make a good box with it.

    Rocker
    Does this mean you are not going to make the octogon box? :eek: I was so looking forward to see what you came up with. Oh well. One thing this thread did is spark an interest in trying this type of lid. That is if i can figure out what the heck was said about the math.

Page 2 of 3 FirstFirst 123 LastLast

Similar Threads

  1. Box Makers Procedure for adoption.
    By Sculptured Box in forum BOX MAKING
    Replies: 5
    Last Post: 29th September 2006, 10:31 PM
  2. Box Makers Mystery Swap
    By Sculptured Box in forum BOX MAKING
    Replies: 41
    Last Post: 27th September 2006, 11:35 PM
  3. Simple Puzzle Box Prototype
    By bitingmidge in forum WOODWORK PICS
    Replies: 17
    Last Post: 6th October 2005, 07:52 PM
  4. what hand plane to choose?
    By EMistral in forum WOODWORK - GENERAL
    Replies: 19
    Last Post: 19th February 2005, 08:29 AM
  5. vac box for template routing
    By soundman in forum ROUTING FORUM
    Replies: 4
    Last Post: 27th July 2002, 11:56 PM

Tags for this Thread

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •