The mundane Mondaine Clock position.
I am not going to consider:
- the time it takes M to accelerate and decelerate in its 6° travel in 1/16 second – it's unknown anyway
- anything to do with quartz
- wear and tear, age, quality, country of manufacture, the weight of any dust on the hands, wind direction, gravitational pull, La Niña effect or any other such ridiculous, pedantic notion to satisfy the 81st Prime Number
Assumptions:
- M starts moving at the very end of each 60 second period, rather than at 59 and 15/16 seconds (i.e. a 1/16 sec before the minute has finished).
- M and H are both symmetrical in their width shape, and are straight
Givens:
- We know that at 1:05 plus 1/16 seconds, M is at the 30° position, and that it only moves every 60 seconds.
- We know that at 1:06, M is still at the 30° position, but 1/16 second later it is at 36°.
- We know that at 1:05, H is at the 32.5° position, and that it advances at a rate of 0.5° per minute or 1/120° per second.
Thus, at 1:06:00, H has moved to 33.0°, and 1/16 seconds later it has moved 1/120/16° or 0.00052° (rounded) and will be at 33.00052°
So when will M be at 33.00052°?
A 1/16 second is 0.0625 seconds so it has to be a little over half of that time to move a little over half the distance (3.00052° of 6° travel)
So 3.00052 / 6 * 0.0625 = 0.03125542534 seconds
At 1:06 plus 0.03126 seconds to the nearest 1/10,000 sec is when the centre of M passes across the centre of H, or more realistically phrased as 1:06 plus 1/32 seconds (in other words plus half the 1/16 second it takes to click forward).