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Thread: Digital Century

  1. #1
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    Default Digital Century

    Place three common mathematical symbols between the digits:

    1 2 3 4 5 6 7 8 9

    So that the result equals 100
    The same symbol can be repeated, but each repeat counts as one the three symbols you must use.
    Rearranging the digits is not permitted.

    Greg

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  3. #2
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    Default

    1x(2+3)x4x5+6789 = 100

  4. #3
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    Default only 3 to be used in total

    Perhaps not.....
    Now try it using only 3 symbols (same symbol can be used more than once)


    Greg

  5. #4
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    Default How about this?

    123-45-67+89 = 100

    ajw

  6. #5
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    Default

    1x2x3x4+5+6-7+8x9

    I wonder how many permutations?

  7. #6
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    Default very impressive

    That was great!
    Now try this one:


    Place a standard mathematical symbol between 4 & 5 to get a number greater than 4 and less than 5.

  8. #7
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    Default

    There would be dozens of possible solutions if you don't limit yourself to 3 mathematical symbols. Even more solutions if you could use parentheses to force an order of calculation.

    ajw

  9. #8
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    Default

    4 + 5 ≠ 4.5

    What do I win?

  10. #9
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    Default

    Actually, still thinking about that one. Let me put one back at you.

    Place a standard mathematical symbol between 4 and 5 to get a number greater than 1000.

  11. #10
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    Default

    Quote Originally Posted by sjt View Post
    Place a standard mathematical symbol between 4 and 5 to get a number greater than 1000.

    Too easy. 4^5=1024


    ajw

  12. #11
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    Default 2 bicycles

    You win the profit from my sale of 2 bicycles.

    I sold one for $300 a loss of 25%
    and another for a gain of 25%.

    How much do you get?

    Greg

  13. #12
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    Default

    Quote Originally Posted by Greg Ward View Post
    That was great!
    Now try this one:


    Place a standard mathematical symbol between 4 & 5 to get a number greater than 4 and less than 5.
    One answer is 4+log(5). Is that the solution you had?

    ajw

  14. #13
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    Default Too complex....

    This one really is just a trick.
    Place a decimal point between 4 & 5 and you get....... 4.5

    A policemen has forgotten his log book and he spots 3 speeding cars. He has a good memory and notes their 4 digit number plates easily as they all contain the same 4 consecutive numbers:
    one, the correct order, one the reverse and the other higgledy-piggledy.
    He also notices the three numbers added together total 12,300.

    What are the number plates?

    Greg

  15. #14
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    Default

    Quote Originally Posted by Greg Ward View Post
    This one really is just a trick.
    Place a decimal point between 4 & 5 and you get....... 4.5

    A policemen has forgotten his log book and he spots 3 speeding cars. He has a good memory and notes their 4 digit number plates easily as they all contain the same 4 consecutive numbers:
    one, the correct order, one the reverse and the other higgledy-piggledy.
    He also notices the three numbers added together total 12,300.

    What are the number plates?

    Greg
    2345, 5432, and 4523

    ajw

  16. #15
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    Default

    Oooh, hats off

    4 + 5 ≠ 4.5. Technically I was correct?

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