Thread: Maths problem 9999

Still want to see your method Wongo, to see what you do here.

Thanks
Greg

good work wongy, greg and russel

Originally Posted by Greg Ward

9 + (square root 9)! + 9/9 = 16

greg

Please be Gentle with me......

OK!
9 = 9,
and
9/9 = 1,
but WTH!!!
(Sq Rt 9)!.......Isn't that 3, NOT 6????? Please Explain

n! = n * n-1 * n-2 * n-3 * ....* 1

for example

4! = 4 * 3 * 2 * 1
1! = 1

By definition 0! = 1


9 + (square root 9)! + 9/9

= 9 + 3! + 9/9
= 9 + 6 + 1
=16

Interesting. I can do 21 and 22, can you?

No takers? Actually, once you have got the idea it becomes almost mundane up to 64. 65 is a bit challenging and now I am stuck at 67. Think I will go back to woodworking. Anybody out there more determined than I am?

I can do 6561 can you?

Originally Posted by Wongo

I can do 6561 can you?

Wow, that was tough! It took me all night, but I finally cracked it!
I still haven't cracked 67 though... does anybody know whether it is even possible?

Originally Posted by Wongo

n! = n * n-1 * n-2 * n-3 * ....* 1

for example

4! = 4 * 3 * 2 * 1
1! = 1

By definition 0! = 1


9 + (square root 9)! + 9/9

= 9 + 3! + 9/9
= 9 + 6 + 1
=16

thanx wongo, was wondering what that meant.

now i will know before every one else when we learn that later this year

Originally Posted by Wongo

Sorry Greg, there were too many ((((((

Starting to look like LISP code

Originally Posted by Frank&Earnest

I still haven't cracked 67 though... does anybody know whether it is even possible?

I tried it but couldn't do it. Sorry.

Thanks Wongo, once worked out that each 9 can be modified by symbols to make 1, 3, 6 and 9 I thought that maybe all integers could be made up with these four numbers, or something silly like that, but it appears that this hypothesis was too far fetched. So, again, back to woodworking!

Originally Posted by Wongo

The "9 squared" bit is a bit dodgy.

What's next 9 thirded, 9 tripled or 9 minus five times four ??

I agree. Squared is the power of 2. That's got a 2 in it.