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16th March 2012, 11:46 AM #31GOLD MEMBER
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Hello all,
Thankyou to everyone who helped shed light on this project waiting to happen!
Being 3 HP certainly allows for some scope with deciding what use to put it to, assuming I can trick the controller into making it work!
Variable speed for my mill is probably at the top of the list of projects for this motor but it will be a long way off. It will sit in my cupboard until I'm ready!
Now, getting back to "tricking the controller", Looking at the controller board you can see that the controller board has inputs. These inputs would normally come from the treadmill control panel where the user would select such conditions as speed, incline etc etc.
The seven inputs into the speed controller are:
1 : GND (no surprises here)
2 : Key (but not physically used or connected)
3 : Enable/Disable (maybe linked to the emergency stop etc)
4 : Speed Count (Assume this sets the speed of the motor. I'm thinking of a square wave input of varying frequency of say 1 - 10 Khz but would have to plug to function generator with a TTL output to verify)
5 : Efast/Slow (Speed of motor maybe set in two parts depending if this pin is hi or low)
6 : Emotor on (Not sure, maybe some feedback circuit)
7 : Ematch (Not sure but it may be a variation of vector control to make sure that the motor maintains the selected speed regardless of how fat/heavy the person is)
Another assumption I have is that all these inputs are digital inputs since they all pass through an optocoupler on the controller board immediately after the data connection.
Based on my assumptions, I'm thinking that I should only need to determine the correct frequency range for pin 4 and then work out whether the other pins are active hi or low..
If I can crack it, then I think it will make a cracking motor and VFD combo for free!
Also id I make a dedicated PIC program and circuit, I could use the input signal on pin 4 to make a dedicated tacho display for it.
Just my ideas on this.....
Cheers,
Simon
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16th March 2012 11:46 AM # ADSGoogle Adsense Advertisement
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16th March 2012, 11:48 AM #32GOLD MEMBER
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16th March 2012, 03:08 PM #33
Hi Simon,
On that CCT it appears to show a lubrication pump? If it's any good that's a handy little bonus.
Regards
Ray
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16th March 2012, 03:17 PM #34GOLD MEMBER
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Hi Ray,
yes I have kept all that, including the motor that raises and lowers the treadmill.
The pump is driven by a small 110V induction motor so I have kept the pump and the transformer that drives it. Was thinking of using the pump to set up a one shot lubrication system and have it plumbed to both the lathe and mill. Just open the valve and run the pump for a few seconds..... something like that anyway.
The actual pump is interesting, it's contained in a small plastic case and contains an arm with two rollers that rotates on a shaft. Inside is a flexible tube that the lubricant flows through and as the rollers move around, it squeezes the tube and forces the lubricant through. Very simple design.
Cheers,
Simon
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16th March 2012, 05:55 PM #35
In the service manual linked, page 50 has the parts list. The first item is Drive Motor 2HP, so I suspect that the unit is actually 2HP rather than 3HP.
Rather a mute point anyway. Electric motors will draw as much current as they need to to handle an imposed load. The power rating is a measure of how much power can be drawn without overheating the motor. Slow the motor, and you slow the fan and reduce cooling flow and hence lower the power rating of the motor unless you have auxiliary cooling fans etc.
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16th March 2012, 06:50 PM #36GOLD MEMBER
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Perhaps the motor is rated to 3 HP but the control board, due to maximum speed restriction of the treadmill will only allow a max. of 2 HP?
So, my mill has come standard with a 2 HP motor. Are you suggesting that I can replace that with a 1 HP, 2 HP or 3 HP variable speed motor and it won't make any difference?
Also, I assume if you slow the motor and slow the cooling fan, then you reduce the power going into it anyway. Isn't that the point?
Simon
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17th March 2012, 09:54 AM #37GOLD MEMBER
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That assumes that the motor is capable of handling the imposed load.
no Simon
if you have a load that requires 3hp you must have a motor that can handle that load...A 1 or 2 hp wont do
putting a 3hp motor on a 1hp load will work...its just inefficient and higher upfront cost...but if you get the motor for zilch then its just inefficient
and your treadmill motor is specifically manufactured for frequency driving(refer motor ID plate) ..most standard motors are not designed for frequency driving much above 60HZ..they work above this but are not manufactured for it
A 400hz VSD/VFD could theoreticaly drive a standard 1440rpm motor to 12000rpm ....(this is synchronous speed)...but the motor would be destroyed if one tried
motors for high frequency input are purpose built.
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17th March 2012, 10:27 AM #38SENIOR MEMBER
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How many wires go into the motor, does it have any brushes?. Nearly all treadmill motors I've seen are variable speed 2Hp DC controlled by PWM speed controllers.
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17th March 2012, 10:50 AM #39GOLD MEMBER
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Hi guys,
According to the wiring diagram 5 wires. Ground, two for a thrm cut out and three labled phase 1, phase 2 and phase 3. The motor has PH. 3 on the label.
Eskimo, I nearly got to see what a 3hp motor looked like at 12000rpm. The manual for my VSDs says the factory setting is 50Hz, it wasnt. Luckily the ramp was set at around 25 seconds.
Stuart
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17th March 2012, 10:59 AM #40SENIOR MEMBER
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17th March 2012, 07:28 PM #41GOLD MEMBER
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Hi Stuart,
What would have happened if you let it go? Can a VSD drive a motor to such hi RPM'S? If so, would it just be a matter of the bearings failing after they reach their limits?
Also, Malb's point has me thinking. When you vary the speed of a 3 ph induction motor via a VSD or VFD, are you actually varying the HP output of the motor as well?
Will a 2 HP motor produce and draw the same current at 500 RPM as it would when it's dialled up to run at 1000 RPM? Is it putting out 2 HP and both speeds?
Now throw in Vectoring, which I assume contains a feedback circuit to ensure the motor speed remains constant regardless of the load which it is under. Does this then change things or does a 2 HP motor always draw 1500 Watts (during running, not start up) regardless of its speed?
I hope I have worded the question properly....
Cheers,
Simon
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17th March 2012, 08:26 PM #42Senior Member
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pump
Hi simonl,
The pump you describe is a peristaltic pump, Wikepedia have a good description.
tinkera
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17th March 2012, 08:38 PM #43GOLD MEMBER
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Hi Tinkera,
You are correct, in fact the picture looks almost identical to the one I have. Glad my more than woeful description at least made some sense! Thanks for the info.
Just in case anyone else is interested here is the link to the Wiki article.
http://upload.wikimedia.org/wikipedi..._pump_head.jpg
What makes this pump perfect for lubrication is firstly it's relatively low output as about what you would need for a lubrication system. Secondly, being a positive displacement pump, you can have the coolant lower than the pump and still not have to worry about priming the pump if air bubbles get into the system since positive displacement pumps will pump gas as well as air. Unlike centrifugal pumps that will only pump fluids.
Cheers,
Simon
Cheers,
Simon
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17th March 2012, 09:14 PM #44
Actually it doesn't make that assumption at all. It's a simple fact that if the motor cannot handle the imposed load, it either trips it's own protection, a fuse or breaker in the supply network, or destroys itself.
The point I was making is that the manufacturers power rating is an indication of the amount of heat that the motor can disipate without damage, not the hard limited input power consumption.
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17th March 2012, 09:32 PM #45
Hmmm... you are assuming the stall current will destroy the motor... What about stepper motors, brushless DC, shaded pole motors etc etc...
The manufacturers power rating is a function of many factors, how the motor is wound, number of turns per lap, wire gauge used, number of poles, how efficiently the magnetic flux is transferred to the rotor and so on... You can't expect to get 10 hp out of a 3 hp motor just by loading it... As you increase the load beyond the torque that the motor is capable of, the motor slows down and the hp ( the work done the motor) decreases linearly with rpm.
hp= torque*rpm / 5252
Lower rpm = lower hp
Regards
Ray
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