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Thread: Compound Angles on Butt Joints
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15th March 2005, 02:45 AM #1New Member
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Compound Angles on Butt Joints
Can anyone please give me the formula for calculating compound angles. I'v trawled the internet for days trying to find the answer or should i say trying to find the answer in simplified terms that i can understand.
Im a PatternMaker by trade so I should really know how to work them out but its been that long ago since doing this as an apprentice that iv completely forgotton and dont have any notes.
I am constructing a tapered box with each side angled back at 11.5 degrees and i need to know how many degrees to back off the Butt Joints to make for a perfect fit.
Many thanks in advance,
Neil.
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15th March 2005 02:45 AM # ADSGoogle Adsense Advertisement
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15th March 2005, 03:53 AM #2
http://home.att.net/~waterfront-wood...oundangles.htm
the above may help you Neil.
beejay1
http://community.webshots.com/user/eunos9
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15th March 2005, 07:24 PM #3New Member
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Cheers Beejay1 but iv already seen that link, to be honest it doesnt mean anything to me, sorry its probably me just being a bit thick. I will carry on looking on the internet today to see what we can see.Thanks again anyway,
Neil.
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15th March 2005, 07:32 PM #4Originally Posted by NeilSheffield
http://www.cabinetmaking.co.uk/compoundangles.htm
good luck mate.
beejay1
http.community.webshots.com/user/eunos9
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16th March 2005, 12:55 AM #5Originally Posted by NeilSheffield
Might need a rough scetch to understand what you mean?
Ok I'll give it a try(may not be correct, prob not!)
Usually you work out by dividing the number of sides into 360* for equal sided construction, but for adding 90* butt joins...
To get a 180* 3 sided arched box lid using 11.5* angled on the sides, you got 2 X 11.5* = 23* - from 180* /2 = 78.5* each way from the centre 90* to cut on the lid for the top centre piece.
Is that what you mean?....................................................................
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16th March 2005, 07:23 AM #6
Usually you work out by dividing the number of sides into 360* for equal sided construction, but for adding 90* butt joins...
To get a 180* 3 sided arched box lid using 11.5* angled on the sides, you got 2 X 11.5* = 23* - from 180* /2 = 78.5* each way from the centre 90* to cut on the lid for the top centre piece.
say wot!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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16th March 2005, 11:06 AM #7
If you have a SCMS and if you are making a four sided box. I would set the tilt angle to 45° and the mitre angle to 11.5° and cut, and if it is more than a four sided box just work out the angle for the tillt degrees.
You do that by dividing 360 by the number of sides in the box and divide the result by 2 and that is the angle to set the tilt at.
If you have a one sided SCMS you will have to set the mitre angle to the opposite side and turn the timber around to cut the other side of the side, if all that makes any sense.
From one Patternmaker to another.
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16th March 2005, 08:52 PM #8New Member
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Corebox
Thanks for the response guys but I feel like you dont quite understand my problem, Im hopefully gonna post a diagram so you can see exactly what I mean. Failing this leave me an E-mail address and i'll forward a sheet on to you personally explaining my problem.
Well iv just tried to add a diagram and failed so allow me to send you a diagram with explanations.
Thanks again, I'll get there in the end.
Hopefully.
Neil.
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17th March 2005, 01:05 AM #9Originally Posted by arms
Thats the way I've used for working out multi angled speaker boxes, works a treat(KIS).....................................................................
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17th March 2005, 07:16 PM #10New Member
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This is the box in question that I require the formula for calculating the compound angles on the butt joints. As I said before the angles of all sides are 11.5 degrees.
Thanks Neil.
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17th March 2005, 07:22 PM #11New Member
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This is a more detailed diagram
Neil.
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17th March 2005, 08:13 PM #12
Hi Neil,
I think youre looking at basic geometry here so hopefully the attached will help you now,,http://www.gomath.com/geometry/triangle.php
beejay1
http://community.webshots.com/user/eunos9
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17th March 2005, 08:24 PM #13
I maybe wrong but I think if the sides of the box are parallel the sides of the ends would be square.
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17th March 2005, 09:35 PM #14
I think I have an answer that doesn't involve trigonometry but should work.
Firstly if you were to calculate the bevel you would need for the side if it was 90* it would be 0*. If you go to the other extreme and assume the "side" was at 0*, ie like the base or the lid, the bevel or "backoff" would be 11.5*. There should be a smooth transition between 11.5* and 0* "backoff" as the angle of the side changes from "0*" to 90* and therefore you should be able to calculate it as a percentage. OK?
ie, 11.5/90 x100 = 12.78%. Therefore the backoff for 11.5* should be 12.78% x 11.5* = 1.47*
Cheers
Michael
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17th March 2005, 10:17 PM #15New Member
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Cheers mate,
I did try that the other day it made a lot of sense but it actually doesnt work, the back off angle doesnt change uniformally. It does require some sort of trigonometry calculation based on the two adjoining angles. If only id taken more note when i was an apprentice.
The angle has been worked out to around 2.3 degrees on a 3D modelling package software, its just that id love to know the actual formula. It cant be much of a formula can it really?
Anyway back to the drawing board, I dont think were ever gonna get to the bottom of this baby.
Thanks Neil..